FA-99561 / RAG context assembly / Open access
Context coverage interleaves document chunks without breaking prefixes · case 01
Context coverage interleaves document chunks without breaking prefixes.
ROOT CAUSE
Assembly emits whole document groups, so later documents receive no context until an earlier source is exhausted.
THE FAILURE
Assembly emits whole document groups, so later documents receive no context until an earlier source is exhausted.
Unsuccessful approach: Sorting each document’s chunks by cost can emit a continuation before its required prefix chunk.
Case contract
Rows are [document,ordinal,text,cost] with unique contiguous ordinals per document. In first-seen document order, emit one next chunk per pass; each document contributes only a contiguous ordinal prefix. Skip a document after its next chunk cannot fit the remaining budget. Return [document,ordinal,text] rows.
Why this case matters
A small deterministic evidence assembly model makes context budgeting behavior inspectable.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(rows, budget):
groups={}; order=[]
for doc,ordinal,text,cost in rows:
if doc not in groups: groups[doc]=[]; order.append(doc)
groups[doc].append((ordinal,[doc,ordinal,text],cost))
return [item for doc in order for ordinal,item,cost in sorted(groups[doc])]
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
a='doc'+str(N); b='other'+str(N)
check('round robin keeps local order', solve([[a,0,'a0',1],[a,1,'a1',1],[b,0,'b0',1],[b,1,'b1',1]],3), [[a,0,'a0'],[b,0,'b0'],[a,1,'a1']])
check('expensive prefix keeps dependency', solve([[a,0,'a0',3],[a,1,'a1',1],[b,0,'b0',1],[b,1,'b1',0]],4), [[a,0,'a0'],[b,0,'b0'],[b,1,'b1']])
check('input order inside source is ordinal', solve([[a,1,'a1',1],[b,0,'b0',1],[a,0,'a0',1]],3), [[a,0,'a0'],[b,0,'b0'],[a,1,'a1']])
check('empty', solve([],N), [])
check('one document prefix', solve([[a,0,'a0',1],[a,1,'a1',1]],2), [[a,0,'a0'],[a,1,'a1']])
check('zero budget blocks positive chunks', solve([[a,0,'a0',1],[b,0,'b0',1]],0), [])
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| round robin keeps local order | [['doc1', 0, 'a0'], ['doc1', 1, 'a1'], ['other1', 0, 'b0'], ['other1', 1, 'b1']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['doc1', 1, 'a1']] | Failed |
| expensive prefix keeps dependency | [['doc1', 0, 'a0'], ['doc1', 1, 'a1'], ['other1', 0, 'b0'], ['other1', 1, 'b1']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['other1', 1, 'b1']] | Failed |
| input order inside source is ordinal | [['doc1', 0, 'a0'], ['doc1', 1, 'a1'], ['other1', 0, 'b0']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['doc1', 1, 'a1']] | Failed |
| empty | [] | [] | Passed |
| one document prefix | [['doc1', 0, 'a0'], ['doc1', 1, 'a1']] | [['doc1', 0, 'a0'], ['doc1', 1, 'a1']] | Passed |
| zero budget blocks positive chunks | [['doc1', 0, 'a0'], ['other1', 0, 'b0']] | [] | Failed |
SHA-256 / 37f48bc313a13910788ca046689cdf4867ba530f9302cddd7451c34964b69669
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(rows, budget):
groups={}; order=[]
for doc,ordinal,text,cost in rows:
if doc not in groups: groups[doc]=[]; order.append(doc)
groups[doc].append((ordinal,[doc,ordinal,text],cost))
for doc in order: groups[doc].sort(key=lambda row:row[2])
out=[]; used=0; pos={doc:0 for doc in order}
while True:
advanced=False
for doc in order:
if pos[doc]<len(groups[doc]):
advanced=True; ordinal,item,cost=groups[doc][pos[doc]]
if used+cost<=budget: out.append(item); used+=cost; pos[doc]+=1
else: pos[doc]=len(groups[doc])
if not advanced: break
return out
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
a='doc'+str(N); b='other'+str(N)
check('round robin keeps local order', solve([[a,0,'a0',1],[a,1,'a1',1],[b,0,'b0',1],[b,1,'b1',1]],3), [[a,0,'a0'],[b,0,'b0'],[a,1,'a1']])
check('expensive prefix keeps dependency', solve([[a,0,'a0',3],[a,1,'a1',1],[b,0,'b0',1],[b,1,'b1',0]],4), [[a,0,'a0'],[b,0,'b0'],[b,1,'b1']])
check('input order inside source is ordinal', solve([[a,1,'a1',1],[b,0,'b0',1],[a,0,'a0',1]],3), [[a,0,'a0'],[b,0,'b0'],[a,1,'a1']])
check('empty', solve([],N), [])
check('one document prefix', solve([[a,0,'a0',1],[a,1,'a1',1]],2), [[a,0,'a0'],[a,1,'a1']])
check('zero budget blocks positive chunks', solve([[a,0,'a0',1],[b,0,'b0',1]],0), [])
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| round robin keeps local order | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['doc1', 1, 'a1']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['doc1', 1, 'a1']] | Passed |
| expensive prefix keeps dependency | [['doc1', 1, 'a1'], ['other1', 1, 'b1'], ['doc1', 0, 'a0']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['other1', 1, 'b1']] | Failed |
| input order inside source is ordinal | [['doc1', 1, 'a1'], ['other1', 0, 'b0'], ['doc1', 0, 'a0']] | [['doc1', 0, 'a0'], ['other1', 0, 'b0'], ['doc1', 1, 'a1']] | Failed |
| empty | [] | [] | Passed |
| one document prefix | [['doc1', 0, 'a0'], ['doc1', 1, 'a1']] | [['doc1', 0, 'a0'], ['doc1', 1, 'a1']] | Passed |
| zero budget blocks positive chunks | [] | [] | Passed |
SHA-256 / 03a5dcea5a4160d476de6d7a557dc39e8ac21a2e5d5ac5ba5170435d3e8b11cc
HELD IN THE MEMBER ARCHIVE
The verified repair and its recorded checks are member-only.
This mechanism has 6 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.
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Sign in to the archive ↗Verification & scope
Toy inputs and token counts only; this does not claim compatibility with a tokenizer, prompt format, or production retrieval system. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-30T16:48:25.802431+00:00.
Case digest / 0108ffaa7ece852ed633339cc40216f8f1a12e8120287d9d2db85b40e7c37403