FA-99366 / Embedding vector normalization / Open access
Weighted pooling divides by token count · case 01
Weighted pooling divides by token count.
ROOT CAUSE
Weighted vector contributions are summed but the total weight is ignored.
THE FAILURE
Weighted vector contributions are summed but the total weight is ignored.
Unsuccessful approach: Dividing by the number of vectors is only correct when weights sum to that count.
Case contract
Pool equal-width vectors with nonnegative weights into a weighted mean; total weight zero or no vectors returns empty.
Why this case matters
A small embedding preparation contract can be checked without a model or retrieval system.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(vectors, weights):
return [sum(w*v[j] for v,w in zip(vectors,weights)) for j in range(len(vectors[0]))] if vectors else []
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('unequal weights', solve([[0,N],[N,2*N]],[1,3]), [3*N/4,7*N/4])
check('equal weights', solve([[N,0],[0,N]],[1,1]), [N/2,N/2])
check('zero total', solve([[N],[2*N]],[0,0]), [])
check('empty rows', solve([],[]), [])
check('one vector', solve([[N,2*N]],[N]), [N,2*N])
check('weighted zero vector', solve([[0,N],[2*N,0]],[0,1]), [2*N,0])
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| unequal weights | [3, 7] | [0.75, 1.75] | Failed |
| equal weights | [1, 1] | [0.5, 0.5] | Failed |
| zero total | [0] | [] | Failed |
| empty rows | [] | [] | Passed |
| one vector | [1, 2] | [1, 2] | Passed |
| weighted zero vector | [2, 0] | [2, 0] | Passed |
SHA-256 / 15934326bc3ff8357e02746e19ce524292aaeff8dfb989bb643a21a201273ba9
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(vectors, weights):
return [sum(w*v[j] for v,w in zip(vectors,weights))/len(vectors) for j in range(len(vectors[0]))] if vectors else []
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('unequal weights', solve([[0,N],[N,2*N]],[1,3]), [3*N/4,7*N/4])
check('equal weights', solve([[N,0],[0,N]],[1,1]), [N/2,N/2])
check('zero total', solve([[N],[2*N]],[0,0]), [])
check('empty rows', solve([],[]), [])
check('one vector', solve([[N,2*N]],[N]), [N,2*N])
check('weighted zero vector', solve([[0,N],[2*N,0]],[0,1]), [2*N,0])
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| unequal weights | [1.5, 3.5] | [0.75, 1.75] | Failed |
| equal weights | [0.5, 0.5] | [0.5, 0.5] | Passed |
| zero total | [0.0] | [] | Failed |
| empty rows | [] | [] | Passed |
| one vector | [1.0, 2.0] | [1, 2] | Passed |
| weighted zero vector | [1.0, 0.0] | [2, 0] | Failed |
SHA-256 / 82cf7bf7535ea1abe512f6caf6b3372f3ff51b44e913f1ccb269513250f3b1ea
HELD IN THE MEMBER ARCHIVE
The verified repair and its recorded checks are member-only.
This mechanism has 6 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.
Every case sharing this mechanism uses the same contract and the same repair, so this one record is held back for all of them.
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Sign in to the archive ↗Verification & scope
Inputs are finite toy vectors or token rows; this contract makes no claim about model quality or production embedding behavior. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-30T16:48:23.555583+00:00.
Case digest / ee2bacd62414b1563c9b4b94333d6cba5e4e9be6ac8996b36335048bddfc5781