FA-94764 / Exam timetabling constraints / Member archive

Under-assigned staff never flagged · case 04

Staff carrying far fewer duties than their share pass the report.

Member previewVariant 4 · 3 implementations · 8 checks per implementation

Case contract

staff [name, FTE percent, duties assigned] and total duties. Each target is total * FTE / sum of FTE rounded half up. Deviation = assigned - target; flag staff whose absolute deviation exceeds one. Return [[name, target, deviation], flagged names].

Why this case matters

Invigilation duties are distributed pro rata to contracted hours; fairness reports drive reallocation.

One recorded failure

Sample boundary fixture

This sample comes from the broken implementation of a controlled reproducer.

Boundary fixture	Actual	Expected	Outcome
regression: deviation flag 1	`[[["st0", 4, 0], ["st1", 9, -2], ["st2", 2, 2], ["st3", 5, 2], ["st4", 4, -4]], ["st2", "st3"]]`	`[[["st0", 4, 0], ["st1", 9, -2], ["st2", 2, 2], ["st3", 5, 2], ["st4", 4, -4]], ["st1", "st2", "st3", "st4"]]`	Failed

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