FA-94763 / Exam timetabling constraints / Member archive

Under-assigned staff never flagged · case 03

Staff carrying far fewer duties than their share pass the report.

Member previewVariant 3 · 3 implementations · 8 checks per implementation

Case contract

staff [name, FTE percent, duties assigned] and total duties. Each target is total * FTE / sum of FTE rounded half up. Deviation = assigned - target; flag staff whose absolute deviation exceeds one. Return [[name, target, deviation], flagged names].

Why this case matters

Invigilation duties are distributed pro rata to contracted hours; fairness reports drive reallocation.

One recorded failure

Sample boundary fixture

This sample comes from the broken implementation of a controlled reproducer.

Boundary fixture	Actual	Expected	Outcome
regression: deviation flag 1	`[[["a", 6, -4], ["b", 3, 2]], ["b"]]`	`[[["a", 6, -4], ["b", 3, 2]], ["a", "b"]]`	Failed

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