FA-94758 / Exam timetabling constraints / Member archive

Fair share computed against full-time headcount · case 03

Targets sum to less than the duties when staff are part-time.

Member previewVariant 3 · 3 implementations · 8 checks per implementation

Case contract

staff [name, FTE percent, duties assigned] and total duties. Each target is total * FTE / sum of FTE rounded half up. Deviation = assigned - target; flag staff whose absolute deviation exceeds one. Return [[name, target, deviation], flagged names].

Why this case matters

Invigilation duties are distributed pro rata to contracted hours; fairness reports drive reallocation.

One recorded failure

Sample boundary fixture

This sample comes from the broken implementation of a controlled reproducer.

Boundary fixture	Actual	Expected	Outcome
regression: fte denominator 1	`[[["a", 1, 0], ["b", 4, 0]], []]`	`[[["a", 3, -2], ["b", 8, -4]], ["a", "b"]]`	Failed

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