FA-94398 / Exam timetabling constraints / Member archive

Split feasibility counts seats in incompatible rooms · case 03

An exam is split into rooms that cannot hold all its candidates, leaving students without seats.

Member previewVariant 3 · 3 implementations · 8 checks per implementation

Case contract

exams [id, size, duration, splittable], rooms [id, capacity]. Exams are placed largest first (ties by id). A room is compatible if empty or holding only exams of the same duration. Place whole in the compatible room with the least sufficient remaining capacity (ties by id); else if splittable and compatible rooms have enough total space, fill them by descending remaining capacity (ties by id), skipping full rooms; else unplaced. Return placements and unplaced ids.

Why this case matters

Room allocation rules (mixed durations, best fit, splitting) are the second hard-constraint family of exam timetabling.

One recorded failure

Sample boundary fixture

This sample comes from the broken implementation of a controlled reproducer.

Boundary fixture	Actual	Expected	Outcome
regression: split feasibility scope 1	`{"placed": {"E0": [["R1", 60], ["R2", 20]], "E1": [["R0", 50], ["R2", 30]], "E3": []}, "unplaced": ["E4", "E2"]}`	`{"placed": {"E0": [["R1", 60], ["R2", 20]], "E1": [["R0", 50], ["R2", 30]]}, "unplaced": ["E4", "E2", "E3"]}`	Failed

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