FA-81251 / Music interval and transposition theory / Open access
Interval inversion by quality and number: octave excluded from perfect intervals · case 01
P8 and P15 are rejected while M8 would be accepted.
ROOT CAUSE
The set of perfect-class numbers omits the octave.
THE FAILURE
The set of perfect-class numbers omits the octave.
Unsuccessful approach: Omitting the fourth instead rejects P4 and accepts M4.
Case contract
Input an interval string: quality from P, M, m, A, d, AA, dd followed by a positive integer. Compound numbers above 8 reduce by 7 until <= 8. P is valid only for 1, 4, 5, 8; M and m only for 2, 3, 6, 7. Inversion maps M<->m, A<->d, AA<->dd, P->P and number n -> 9-n. Invalid input returns None.
Why this case matters
Pitch spelling and interval arithmetic decide the notes that notation, transposition and analysis tools display or play.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(x):
swap = {'M': 'm', 'm': 'M', 'A': 'd', 'd': 'A', 'AA': 'dd', 'dd': 'AA', 'P': 'P'}
if not isinstance(x, str):
return None
q = x.rstrip('0123456789')
digits = x[len(q):]
if q not in swap or not digits.isdigit() or int(digits) < 1:
return None
n = int(digits)
while n > 8:
n -= 7
perfect = n in (1, 4, 5)
if (q == 'P' and not perfect) or (q in ('M', 'm') and perfect):
return None
return swap[q] + str(9 - n)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[('M3', 'm6'), ('m3', 'M6'), ('P5', 'P4'), ('P4', 'P5'), ('P1', 'P8'), ('P8', 'P1'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P1', 'P8'), ('P8', 'P1'), ('A4', 'd5'), ('d5', 'A4'), ('M2', 'm7'), ('P15', 'P1'), ('M4', None)], [('P4', 'P5'), ('M2', 'm7'), ('m7', 'M2'), ('M10', 'm6'), ('P15', 'P1'), ('P12', 'P4'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P8', 'P1'), ('P12', 'P4'), ('AA4', 'dd5'), ('dd5', 'AA4'), ('A1', 'd8'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P8', 'P1'), ('P15', 'P1'), ('A1', 'd8'), ('d8', 'A1'), ('M6', 'm3'), ('m9', 'M7'), ('M4', None)]]
for i, (args, expected) in enumerate(fixtures[N-1]):
check("oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| oracle 0 | m6 | m6 | Passed |
| oracle 1 | M6 | M6 | Passed |
| oracle 2 | P4 | P4 | Passed |
| oracle 3 | P5 | P5 | Passed |
| oracle 4 | P8 | P8 | Passed |
| oracle 5 | None | P1 | Failed |
| oracle 6 | None | None | Passed |
| oracle 7 | None | P1 | Failed |
SHA-256 / 19bccbf8d032fd7e7f1bfb29b0de15014c67acdf5533320cfffcb4ec0a4c0980
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
N = 1
observations = []
def solve(x):
swap = {'M': 'm', 'm': 'M', 'A': 'd', 'd': 'A', 'AA': 'dd', 'dd': 'AA', 'P': 'P'}
if not isinstance(x, str):
return None
q = x.rstrip('0123456789')
digits = x[len(q):]
if q not in swap or not digits.isdigit() or int(digits) < 1:
return None
n = int(digits)
while n > 8:
n -= 7
perfect = n in (1, 5, 8)
if (q == 'P' and not perfect) or (q in ('M', 'm') and perfect):
return None
return swap[q] + str(9 - n)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[('M3', 'm6'), ('m3', 'M6'), ('P5', 'P4'), ('P4', 'P5'), ('P1', 'P8'), ('P8', 'P1'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P1', 'P8'), ('P8', 'P1'), ('A4', 'd5'), ('d5', 'A4'), ('M2', 'm7'), ('P15', 'P1'), ('M4', None)], [('P4', 'P5'), ('M2', 'm7'), ('m7', 'M2'), ('M10', 'm6'), ('P15', 'P1'), ('P12', 'P4'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P8', 'P1'), ('P12', 'P4'), ('AA4', 'dd5'), ('dd5', 'AA4'), ('A1', 'd8'), ('M4', None), ('P22', 'P1')], [('P4', 'P5'), ('P8', 'P1'), ('P15', 'P1'), ('A1', 'd8'), ('d8', 'A1'), ('M6', 'm3'), ('m9', 'M7'), ('M4', None)]]
for i, (args, expected) in enumerate(fixtures[N-1]):
check("oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| oracle 0 | m6 | m6 | Passed |
| oracle 1 | M6 | M6 | Passed |
| oracle 2 | P4 | P4 | Passed |
| oracle 3 | None | P5 | Failed |
| oracle 4 | P8 | P8 | Passed |
| oracle 5 | P1 | P1 | Passed |
| oracle 6 | m5 | None | Failed |
| oracle 7 | P1 | P1 | Passed |
SHA-256 / cedc6d39d6a70db275cbade2ed79e7f2865b94833af6ec758860582083796487
HELD IN THE MEMBER ARCHIVE
The verified repair and its recorded checks are member-only.
This mechanism has 8 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.
Every case sharing this mechanism uses the same contract and the same repair, so this one record is held back for all of them.
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Sign in to the archive ↗Verification & scope
A deterministic bounded teaching model with a stipulated toy contract; it is not a complete music notation or theory engine. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-29T14:50:01.253820+00:00.
Case digest / 9aa8b35100ca7da76aa327677b9e10bf50e71c69df00c7e43e2a55e285dffd8e