FA-66604 / Airline fare rule evaluation / Member archive

Free tickets counted against total travellers · case 04

A group of 15 receives a free ticket although only 14 would then be paying.

Member previewVariant 4 · 3 implementations · 11 checks per implementation

Case contract

Input {'pax','min_group','free_per','fare','disc_pct'}. Below min_group (total travellers) no discount and no free tickets. Otherwise one free ticket per free_per paying travellers (free = pax // (free_per+1)); each paying fare = fare*(100-disc)/100 rounded to cents, then multiplied. Return [paying, free, total r2].

Why this case matters

Group fares apply a discount once a minimum size is reached and grant tour-conductor tickets that must not themselves count as paying passengers.

One recorded failure

Sample boundary fixture

This sample comes from the broken implementation of a controlled reproducer.

Boundary fixture	Actual	Expected	Outcome
fifteen travellers none free	`[14, 1, 2569.84]`	`[15, 0, 2753.4]`	Failed

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