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FA-6466 / Discrete calculus / Open access

Discrete energy squared norm · case 01

Squaring the total allows cancellation between samples.

Verified by executionVariant 1 · 4 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

Squaring the total allows cancellation between samples.

VERIFIED REPAIR

Apply the specified mathematical contract directly, preserving all terms and boundary cases: return sum(v*v for v in values)

Unsuccessful approach: Magnitude sum is not quadratic energy.

Case contract

Integer sample values and compatible sample-array lengths. Rational results are reduced Fraction strings; spacing is positive unless explicitly stated otherwise. Discrete energy squared norm. Exact operational definition: sum(v*v for v in values)

Why this case matters

Small exact fixtures expose this error without platform timing, external services, or probabilistic observations. Discrete calculus results depend on the stated convention.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return sum(values)**2
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([2, -2],)', solve(*([2, -2],)), 8)
check('fixture 2: ([1, 2, 3],)', solve(*([1, 2, 3],)), 14)
check('fixture 3: ([0],)', solve(*([0],)), 0)
check('fixture 4: ([],)', solve(*([],)), 0)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([2, -2],)08Failed
fixture 2: ([1, 2, 3],)3614Failed
fixture 3: ([0],)00Passed
fixture 4: ([],)00Passed

SHA-256 / c57058ca4a9bee9818150b77deb625f25878b00b2694d0745d1ead243eea3fa0

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return sum(abs(v) for v in values)
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([2, -2],)', solve(*([2, -2],)), 8)
check('fixture 2: ([1, 2, 3],)', solve(*([1, 2, 3],)), 14)
check('fixture 3: ([0],)', solve(*([0],)), 0)
check('fixture 4: ([],)', solve(*([],)), 0)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([2, -2],)48Failed
fixture 2: ([1, 2, 3],)614Failed
fixture 3: ([0],)00Passed
fixture 4: ([],)00Passed

SHA-256 / 7dd3f5bfd57ad3c550c98d8b81d7157636826af31e4174f485b00637567e8d50

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return sum(v*v for v in values)
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([2, -2],)', solve(*([2, -2],)), 8)
check('fixture 2: ([1, 2, 3],)', solve(*([1, 2, 3],)), 14)
check('fixture 3: ([0],)', solve(*([0],)), 0)
check('fixture 4: ([],)', solve(*([],)), 0)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([2, -2],)88Passed
fixture 2: ([1, 2, 3],)1414Passed
fixture 3: ([0],)00Passed
fixture 4: ([],)00Passed

SHA-256 / 5da0a89029fab5d5331daa283748ec86573cd8259cd34cd3eebc3b7bd8079093

Verification & scope

This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:38:02.369070+00:00.

Case digest / 17f6157cbdb66003949d8ada59300ebe165557c243476f90c797f7098611395b