FA-6266 / Statistics / Open access
Mean squared error · case 01
Averaging before squaring permits residual cancellation.
ROOT CAUSE
Averaging before squaring permits residual cancellation.
THE FAILURE
Averaging before squaring permits residual cancellation.
Unsuccessful approach: Absolute residuals implement a different loss.
Case contract
Integer finite observations and equal lengths for paired samples. Counts and weights are nonnegative. Rational results use reduced Fraction strings. Empty or undefined statistics return None where shown. Paired arrays are nonempty; average squared prediction residuals. Exact operational definition: str(Fraction(sum((a-p)**2 for a,p in zip(actual,predicted)),len(actual)))
Why this case matters
Small exact fixtures expose this error without platform timing, external services, or probabilistic observations. Statistical estimators results depend on the stated convention.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR
N = 1
observations = []
def solve(actual, predicted):
return str(Fraction(sum(a-p for a,p in zip(actual,predicted)),len(actual))**2)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 3], [2, 2])', solve(*([1, 3], [2, 2])), '1')
check('fixture 2: ([0, 0], [2, -2])', solve(*([0, 0], [2, -2])), '4')
check('fixture 3: ([1], [1])', solve(*([1], [1])), '0')
check('fixture 4: ([1, 2, 3], [1, 2, 6])', solve(*([1, 2, 3], [1, 2, 6])), '3')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| fixture 1: ([1, 3], [2, 2]) | 0 | 1 | Failed |
| fixture 2: ([0, 0], [2, -2]) | 0 | 4 | Failed |
| fixture 3: ([1], [1]) | 0 | 0 | Passed |
| fixture 4: ([1, 2, 3], [1, 2, 6]) | 1 | 3 | Failed |
SHA-256 / 00f96a0b117eecd8f5336ffeedc2340c0d611e305b63b9ad2bfc0d43e28802d0
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR
N = 1
observations = []
def solve(actual, predicted):
return str(Fraction(sum(abs(a-p) for a,p in zip(actual,predicted)),len(actual)))
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 3], [2, 2])', solve(*([1, 3], [2, 2])), '1')
check('fixture 2: ([0, 0], [2, -2])', solve(*([0, 0], [2, -2])), '4')
check('fixture 3: ([1], [1])', solve(*([1], [1])), '0')
check('fixture 4: ([1, 2, 3], [1, 2, 6])', solve(*([1, 2, 3], [1, 2, 6])), '3')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| fixture 1: ([1, 3], [2, 2]) | 1 | 1 | Passed |
| fixture 2: ([0, 0], [2, -2]) | 2 | 4 | Failed |
| fixture 3: ([1], [1]) | 0 | 0 | Passed |
| fixture 4: ([1, 2, 3], [1, 2, 6]) | 1 | 3 | Failed |
SHA-256 / fa83a3d61905051baadbbf48424318c953ee8b99423bb6b0ba8d6dcb458ac4da
HELD IN THE MEMBER ARCHIVE
The verified repair and its recorded checks are member-only.
This mechanism has 4 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.
Every case sharing this mechanism uses the same contract and the same repair, so this one record is held back for all of them.
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Sign in to the archive ↗Verification & scope
This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-29T14:37:59.557005+00:00.
Case digest / f388f8016e4bb9b493a321a16434115be15d7b35eb6a320b4010200d29bdb221