FAILURE MAP
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FA-6246 / Statistics / Open access

Linear regression slope rational · case 01

The ratio of means incorrectly forces the fitted line through zero.

Verified by executionVariant 1 · 4 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

The ratio of means incorrectly forces the fitted line through zero.

VERIFIED REPAIR

Apply the specified mathematical contract directly, preserving all terms and boundary cases: return str(Fraction(len(x)*sum(a*b for a,b in zip(x,y))-sum(x)*sum(y),len(x)*sum(a*a for a in x)-sum(x)**2)) if len(x)*sum(a*a for a in x)!=sum(x)**2 else None

Unsuccessful approach: Dependent-variable variance replaces independent-variable variance.

Case contract

Integer finite observations and equal lengths for paired samples. Counts and weights are nonnegative. Rational results use reduced Fraction strings. Empty or undefined statistics return None where shown. Fit y=intercept+slope*x by least squares; return None when x variance is zero, including empty input. Exact operational definition: str(Fraction(len(x)*sum(a*b for a,b in zip(x,y))-sum(x)*sum(y),len(x)*sum(a*a for a in x)-sum(x)**2)) if len(x)*sum(a*a for a in x)!=sum(x)**2 else None

Why this case matters

Small exact fixtures expose this error without platform timing, external services, or probabilistic observations. Statistical estimators results depend on the stated convention.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(x, y):
    return str(Fraction(sum(y),sum(x))) if sum(x) else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 3], [3, 5, 7])', solve(*([1, 2, 3], [3, 5, 7])), '2')
check('fixture 2: ([1, 2, 3], [3, 2, 1])', solve(*([1, 2, 3], [3, 2, 1])), '-1')
check('fixture 3: ([1, 1], [2, 3])', solve(*([1, 1], [2, 3])), None)
check('fixture 4: ([0, 1], [2, 2])', solve(*([0, 1], [2, 2])), '0')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 3], [3, 5, 7])5/22Failed
fixture 2: ([1, 2, 3], [3, 2, 1])1-1Failed
fixture 3: ([1, 1], [2, 3])5/2NoneFailed
fixture 4: ([0, 1], [2, 2])40Failed

SHA-256 / b5c822a33bc653dc7f35baf9fd8ebfc8a45c78c2e38523f6a1615638dce0a05a

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(x, y):
    return str(Fraction(len(x)*sum(a*b for a,b in zip(x,y))-sum(x)*sum(y),len(x)*sum(b*b for b in y)-sum(y)**2)) if len(x)*sum(b*b for b in y)!=sum(y)**2 else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 3], [3, 5, 7])', solve(*([1, 2, 3], [3, 5, 7])), '2')
check('fixture 2: ([1, 2, 3], [3, 2, 1])', solve(*([1, 2, 3], [3, 2, 1])), '-1')
check('fixture 3: ([1, 1], [2, 3])', solve(*([1, 1], [2, 3])), None)
check('fixture 4: ([0, 1], [2, 2])', solve(*([0, 1], [2, 2])), '0')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 3], [3, 5, 7])1/22Failed
fixture 2: ([1, 2, 3], [3, 2, 1])-1-1Passed
fixture 3: ([1, 1], [2, 3])0NoneFailed
fixture 4: ([0, 1], [2, 2])None0Failed

SHA-256 / 1723bf98656ba35378e04bf30d78e1f21d9dfaf7f0ad60fc809178bac0bcf034

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(x, y):
    return str(Fraction(len(x)*sum(a*b for a,b in zip(x,y))-sum(x)*sum(y),len(x)*sum(a*a for a in x)-sum(x)**2)) if len(x)*sum(a*a for a in x)!=sum(x)**2 else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 3], [3, 5, 7])', solve(*([1, 2, 3], [3, 5, 7])), '2')
check('fixture 2: ([1, 2, 3], [3, 2, 1])', solve(*([1, 2, 3], [3, 2, 1])), '-1')
check('fixture 3: ([1, 1], [2, 3])', solve(*([1, 1], [2, 3])), None)
check('fixture 4: ([0, 1], [2, 2])', solve(*([0, 1], [2, 2])), '0')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 3], [3, 5, 7])22Passed
fixture 2: ([1, 2, 3], [3, 2, 1])-1-1Passed
fixture 3: ([1, 1], [2, 3])NoneNonePassed
fixture 4: ([0, 1], [2, 2])00Passed

SHA-256 / 11003650346ceae33747e10e6a637ad5df5eabeb82e904b0f9883fe2068916d5

Verification & scope

This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:37:59.417271+00:00.

Case digest / 2a5ae9ca5f21d4fcdc5f52076631f10f24cec48cba0054c6f7fd12b7a533836d