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Median even middle average · case 01

Only the upper central observation is selected for even samples.

Verified by executionVariant 1 · 4 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

Only the upper central observation is selected for even samples.

VERIFIED REPAIR

Apply the specified mathematical contract directly, preserving all terms and boundary cases: return str(statistics.median([Fraction(v) for v in values])) if values else None

Unsuccessful approach: The midrange substitutes extremes for middle order statistics.

Case contract

Integer finite observations and equal lengths for paired samples. Counts and weights are nonnegative. Rational results use reduced Fraction strings. Empty or undefined statistics return None where shown. Median even middle average. Exact operational definition: str(statistics.median([Fraction(v) for v in values])) if values else None

Why this case matters

Small exact fixtures expose this error without platform timing, external services, or probabilistic observations. Statistical estimators results depend on the stated convention.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return str(sorted(values)[len(values)//2]) if values else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 8, 9],)', solve(*([1, 2, 8, 9],)), '5')
check('fixture 2: ([1, 2, 100],)', solve(*([1, 2, 100],)), '2')
check('fixture 3: ([4],)', solve(*([4],)), '4')
check('fixture 4: ([],)', solve(*([],)), None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 8, 9],)85Failed
fixture 2: ([1, 2, 100],)22Passed
fixture 3: ([4],)44Passed
fixture 4: ([],)NoneNonePassed

SHA-256 / ed2d7861e9c2518a251c8509716ece49b079cd3b6d641456fd0f9f3a8a143b78

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return str(Fraction(min(values)+max(values),2)) if values else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 8, 9],)', solve(*([1, 2, 8, 9],)), '5')
check('fixture 2: ([1, 2, 100],)', solve(*([1, 2, 100],)), '2')
check('fixture 3: ([4],)', solve(*([4],)), '4')
check('fixture 4: ([],)', solve(*([],)), None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 8, 9],)55Passed
fixture 2: ([1, 2, 100],)101/22Failed
fixture 3: ([4],)44Passed
fixture 4: ([],)NoneNonePassed

SHA-256 / dde3468f11b33cc34fc662ade151c8acff92bf29e17fc6649af62e82fa22c667

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import calendar
import statistics
import itertools
from fractions import Fraction
from datetime import date, datetime, timedelta, timezone
from decimal import Decimal, ROUND_HALF_UP, ROUND_DOWN, ROUND_CEILING, ROUND_FLOOR

N = 1
observations = []
def solve(values):
    return str(statistics.median([Fraction(v) for v in values])) if values else None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1: ([1, 2, 8, 9],)', solve(*([1, 2, 8, 9],)), '5')
check('fixture 2: ([1, 2, 100],)', solve(*([1, 2, 100],)), '2')
check('fixture 3: ([4],)', solve(*([4],)), '4')
check('fixture 4: ([],)', solve(*([],)), None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
fixture 1: ([1, 2, 8, 9],)55Passed
fixture 2: ([1, 2, 100],)22Passed
fixture 3: ([4],)44Passed
fixture 4: ([],)NoneNonePassed

SHA-256 / 67522f30edb4a153ba89367b52fbb80ef0d1494e35cd6c9329e383fa9b5f12b5

Verification & scope

This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:37:58.610348+00:00.

Case digest / 9600ec513c8ba1d356c28c9140db71f1d67b3969ee0de08972f29fbd106f84dc