FAILURE MAP
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FA-42896 / Borrow checking / Open access

Common valid lifetime includes points valid for only one referent · case 01

Common valid lifetime includes points valid for only one referent.

Verified by executionVariant 1 · 17 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

The static analyzer mishandles required intersection: common valid lifetime includes points valid for only one referent.

VERIFIED REPAIR

Apply the specified transfer or inference rule at this site: if op=='meet': return sorted(x.intersection(regions[b])).

Unsuccessful approach: The partial repair uses if op=='meet': return sorted(x), which still violates the stipulated analysis contract.

Case contract

Finite lexical regions map names to sets of program-point integers. Longer region contains every point of shorter. Queries: outlives(a,b), meet(a,b), join(a,b), missing(a,b), strict(a,b), eq(a,b), disjoint(a,b), covers(a, list-of-regions), gap(a,b,c) requires a cover intersection of b,c, and choose(a,candidates) returns lexically sorted candidate regions containing a with smallest cardinality, ties lexical. Return booleans or sorted lists as appropriate.

Why this case matters

A finite offline static-analysis model of ownership and borrowing; it does not execute the analyzed program.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json

N = 1
observations = []
def solve(regions, op, a, b, c=None):
    x=set(regions[a])
    if op=='outlives': return x.issuperset(regions[b])
    if op=='meet': return sorted(x.union(regions[b]))
    if op=='join': return sorted(x.union(regions[b]))
    if op=='missing': return sorted(set(regions[b])-x)
    if op=='strict': return x>set(regions[b])
    if op=='eq': return x==set(regions[b])
    if op=='disjoint': return x.isdisjoint(regions[b])
    if op=='covers': return all(x.issuperset(regions[k]) for k in b)
    if op=='gap': return sorted((set(regions[b]) & set(regions[c]))-x)
    if op=='choose':
        candidates=[k for k in b if set(regions[k]).issuperset(x)]
        return min(candidates,key=lambda k:(len(set(regions[k])),k)) if candidates else None
    return None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
r={'a':[N,N+1],'b':[N+1,N+2],'s':[N+1],'e':[],'z':[N+1,N],'aa':[N,N+1,N+2]}
check('outlives',solve(r,'outlives','a','s'),True)
check('incomparable',solve(r,'outlives','a','b'),False)
check('meet',solve(r,'meet','a','b'),[N+1])
check('join',solve(r,'join','a','b'),[N,N+1,N+2])
check('missing',solve(r,'missing','a','b'),[N+2])
check('strict equal',solve(r,'strict','a','a'),False)
check('strict incomparable',solve(r,'strict','aa','b'),True)
check('strict size insufficient',solve({'a':[N,N+1],'b':[N+2]},'strict','a','b'),False)
check('equivalent unordered',solve(r,'eq','a','z'),True)
check('equivalent distinct',solve(r,'eq','a','b'),False)
check('nonempty disjoint',solve({'a':[N],'b':[N+1]},'disjoint','a','b'),True)
check('overlap disjoint',solve(r,'disjoint','a','b'),False)
check('mixed obligations',solve(r,'covers','a',['s','b']),False)
check('no obligations',solve(r,'covers','a',[]),True)
check('joint demand',solve(r,'gap','e','a','b'),[N+1])
check('choose shortest',solve(r,'choose','s',['aa','a','s']), 's')
check('no candidate',solve(r,'choose','aa',['a','s']),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
outlivesTrueTruePassed
incomparableFalseFalsePassed
meet[1, 2, 3][2]Failed
join[1, 2, 3][1, 2, 3]Passed
missing[3][3]Passed
strict equalFalseFalsePassed
strict incomparableTrueTruePassed
strict size insufficientFalseFalsePassed
equivalent unorderedTrueTruePassed
equivalent distinctFalseFalsePassed
nonempty disjointTrueTruePassed
overlap disjointFalseFalsePassed
mixed obligationsFalseFalsePassed
no obligationsTrueTruePassed
joint demand[2][2]Passed
choose shortestssPassed
no candidateNoneNonePassed

SHA-256 / 56464f0b41703bdd45f6ab9e2b4756c4908f2f6b45b3f6f44113c05180e33192

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json

N = 1
observations = []
def solve(regions, op, a, b, c=None):
    x=set(regions[a])
    if op=='outlives': return x.issuperset(regions[b])
    if op=='meet': return sorted(x)
    if op=='join': return sorted(x.union(regions[b]))
    if op=='missing': return sorted(set(regions[b])-x)
    if op=='strict': return x>set(regions[b])
    if op=='eq': return x==set(regions[b])
    if op=='disjoint': return x.isdisjoint(regions[b])
    if op=='covers': return all(x.issuperset(regions[k]) for k in b)
    if op=='gap': return sorted((set(regions[b]) & set(regions[c]))-x)
    if op=='choose':
        candidates=[k for k in b if set(regions[k]).issuperset(x)]
        return min(candidates,key=lambda k:(len(set(regions[k])),k)) if candidates else None
    return None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
r={'a':[N,N+1],'b':[N+1,N+2],'s':[N+1],'e':[],'z':[N+1,N],'aa':[N,N+1,N+2]}
check('outlives',solve(r,'outlives','a','s'),True)
check('incomparable',solve(r,'outlives','a','b'),False)
check('meet',solve(r,'meet','a','b'),[N+1])
check('join',solve(r,'join','a','b'),[N,N+1,N+2])
check('missing',solve(r,'missing','a','b'),[N+2])
check('strict equal',solve(r,'strict','a','a'),False)
check('strict incomparable',solve(r,'strict','aa','b'),True)
check('strict size insufficient',solve({'a':[N,N+1],'b':[N+2]},'strict','a','b'),False)
check('equivalent unordered',solve(r,'eq','a','z'),True)
check('equivalent distinct',solve(r,'eq','a','b'),False)
check('nonempty disjoint',solve({'a':[N],'b':[N+1]},'disjoint','a','b'),True)
check('overlap disjoint',solve(r,'disjoint','a','b'),False)
check('mixed obligations',solve(r,'covers','a',['s','b']),False)
check('no obligations',solve(r,'covers','a',[]),True)
check('joint demand',solve(r,'gap','e','a','b'),[N+1])
check('choose shortest',solve(r,'choose','s',['aa','a','s']), 's')
check('no candidate',solve(r,'choose','aa',['a','s']),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
outlivesTrueTruePassed
incomparableFalseFalsePassed
meet[1, 2][2]Failed
join[1, 2, 3][1, 2, 3]Passed
missing[3][3]Passed
strict equalFalseFalsePassed
strict incomparableTrueTruePassed
strict size insufficientFalseFalsePassed
equivalent unorderedTrueTruePassed
equivalent distinctFalseFalsePassed
nonempty disjointTrueTruePassed
overlap disjointFalseFalsePassed
mixed obligationsFalseFalsePassed
no obligationsTrueTruePassed
joint demand[2][2]Passed
choose shortestssPassed
no candidateNoneNonePassed

SHA-256 / caabb5fbcb095796683611a93b885a083ade020a79462e1a7f460c946835dd52

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json

N = 1
observations = []
def solve(regions, op, a, b, c=None):
    x=set(regions[a])
    if op=='outlives': return x.issuperset(regions[b])
    if op=='meet': return sorted(x.intersection(regions[b]))
    if op=='join': return sorted(x.union(regions[b]))
    if op=='missing': return sorted(set(regions[b])-x)
    if op=='strict': return x>set(regions[b])
    if op=='eq': return x==set(regions[b])
    if op=='disjoint': return x.isdisjoint(regions[b])
    if op=='covers': return all(x.issuperset(regions[k]) for k in b)
    if op=='gap': return sorted((set(regions[b]) & set(regions[c]))-x)
    if op=='choose':
        candidates=[k for k in b if set(regions[k]).issuperset(x)]
        return min(candidates,key=lambda k:(len(set(regions[k])),k)) if candidates else None
    return None
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
r={'a':[N,N+1],'b':[N+1,N+2],'s':[N+1],'e':[],'z':[N+1,N],'aa':[N,N+1,N+2]}
check('outlives',solve(r,'outlives','a','s'),True)
check('incomparable',solve(r,'outlives','a','b'),False)
check('meet',solve(r,'meet','a','b'),[N+1])
check('join',solve(r,'join','a','b'),[N,N+1,N+2])
check('missing',solve(r,'missing','a','b'),[N+2])
check('strict equal',solve(r,'strict','a','a'),False)
check('strict incomparable',solve(r,'strict','aa','b'),True)
check('strict size insufficient',solve({'a':[N,N+1],'b':[N+2]},'strict','a','b'),False)
check('equivalent unordered',solve(r,'eq','a','z'),True)
check('equivalent distinct',solve(r,'eq','a','b'),False)
check('nonempty disjoint',solve({'a':[N],'b':[N+1]},'disjoint','a','b'),True)
check('overlap disjoint',solve(r,'disjoint','a','b'),False)
check('mixed obligations',solve(r,'covers','a',['s','b']),False)
check('no obligations',solve(r,'covers','a',[]),True)
check('joint demand',solve(r,'gap','e','a','b'),[N+1])
check('choose shortest',solve(r,'choose','s',['aa','a','s']), 's')
check('no candidate',solve(r,'choose','aa',['a','s']),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
outlivesTrueTruePassed
incomparableFalseFalsePassed
meet[2][2]Passed
join[1, 2, 3][1, 2, 3]Passed
missing[3][3]Passed
strict equalFalseFalsePassed
strict incomparableTrueTruePassed
strict size insufficientFalseFalsePassed
equivalent unorderedTrueTruePassed
equivalent distinctFalseFalsePassed
nonempty disjointTrueTruePassed
overlap disjointFalseFalsePassed
mixed obligationsFalseFalsePassed
no obligationsTrueTruePassed
joint demand[2][2]Passed
choose shortestssPassed
no candidateNoneNonePassed

SHA-256 / 96edea118f7a3dfe79867e896f40641c6e4c7a17dd487f924ed6f170809fbc79

Verification & scope

The explicitly stated toy language is the complete scope; this is not a production compiler or a claim about Rust semantics. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:43:56.379821+00:00.

Case digest / 4081b07c137f9130c3259908ffb71915be41d5433ff071956d2cc0f99e26fb96