FAILURE MAP
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FA-15926 / Floating-point arithmetic / Open access

Zero ULP is rounded to zero · case 01

Zero ULP is rounded to zero.

Verified by executionVariant 1 · 9 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

Zero ULP is rounded to zero. The faulty expression is if x == 0: return 0.0.hex().

VERIFIED REPAIR

Apply the contract at this fault site using if x == 0: return float.fromhex('0x0.0000000000001p-1022').hex().

Unsuccessful approach: The attempted local correction if x == 0: return float.fromhex('0x1p-1022').hex() still violates the explicit regression fixtures.

Case contract

Return a finite binary64 ulp as a hex string; NaN maps to nan and either infinity maps to infinity. For subnormals and zero the ulp is the minimum positive subnormal.

Why this case matters

An offline floating representation model isolates a reproducible arithmetic fault.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import struct
N = 1
observations = []
def solve(bits):
    x=struct.unpack('>d',bits.to_bytes(8,'big'))[0]
    if math.isnan(x): return 'nan'
    if math.isinf(x): return 'infinity'
    x=abs(x)
    if x == 0: return 0.0.hex()
    m,e=math.frexp(x)
    e=max(e-53,-1074)
    return math.ldexp(1.0,e).hex()
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('zero', solve(0), '0x0.0000000000001p-1022')
check('negative zero', solve(1<<63), '0x0.0000000000001p-1022')
check('subnormal', solve(N), '0x0.0000000000001p-1022')
check('power boundary', solve((1023+N)<<52), math.ldexp(1.0,N-52).hex())
check('negative power', solve((1<<63)|((1023+N)<<52)), math.ldexp(1.0,N-52).hex())
check('below power', solve(((1023+N)<<52)-1), math.ldexp(1.0,N-53).hex())
check('infinity', solve(0x7ff0000000000000), 'infinity')
check('nan', solve(0x7ff8000000000000|N), 'nan')
check('maximum', solve(0x7fefffffffffffff), '0x1.0000000000000p+971')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
zero0x0.0p+00x0.0000000000001p-1022Failed
negative zero0x0.0p+00x0.0000000000001p-1022Failed
subnormal0x0.0000000000001p-10220x0.0000000000001p-1022Passed
power boundary0x1.0000000000000p-510x1.0000000000000p-51Passed
negative power0x1.0000000000000p-510x1.0000000000000p-51Passed
below power0x1.0000000000000p-520x1.0000000000000p-52Passed
infinityinfinityinfinityPassed
nannannanPassed
maximum0x1.0000000000000p+9710x1.0000000000000p+971Passed

SHA-256 / 987d6fb95b6b5d0c4e4973fa1f2a37d902f49f43ac9e8c54ff9897288502c27a

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import struct
N = 1
observations = []
def solve(bits):
    x=struct.unpack('>d',bits.to_bytes(8,'big'))[0]
    if math.isnan(x): return 'nan'
    if math.isinf(x): return 'infinity'
    x=abs(x)
    if x == 0: return float.fromhex('0x1p-1022').hex()
    m,e=math.frexp(x)
    e=max(e-53,-1074)
    return math.ldexp(1.0,e).hex()
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('zero', solve(0), '0x0.0000000000001p-1022')
check('negative zero', solve(1<<63), '0x0.0000000000001p-1022')
check('subnormal', solve(N), '0x0.0000000000001p-1022')
check('power boundary', solve((1023+N)<<52), math.ldexp(1.0,N-52).hex())
check('negative power', solve((1<<63)|((1023+N)<<52)), math.ldexp(1.0,N-52).hex())
check('below power', solve(((1023+N)<<52)-1), math.ldexp(1.0,N-53).hex())
check('infinity', solve(0x7ff0000000000000), 'infinity')
check('nan', solve(0x7ff8000000000000|N), 'nan')
check('maximum', solve(0x7fefffffffffffff), '0x1.0000000000000p+971')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
zero0x1.0000000000000p-10220x0.0000000000001p-1022Failed
negative zero0x1.0000000000000p-10220x0.0000000000001p-1022Failed
subnormal0x0.0000000000001p-10220x0.0000000000001p-1022Passed
power boundary0x1.0000000000000p-510x1.0000000000000p-51Passed
negative power0x1.0000000000000p-510x1.0000000000000p-51Passed
below power0x1.0000000000000p-520x1.0000000000000p-52Passed
infinityinfinityinfinityPassed
nannannanPassed
maximum0x1.0000000000000p+9710x1.0000000000000p+971Passed

SHA-256 / bdc041cd76c4b186568495307aede089a326fe97d5888931e92556b460f2e2de

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import struct
N = 1
observations = []
def solve(bits):
    x=struct.unpack('>d',bits.to_bytes(8,'big'))[0]
    if math.isnan(x): return 'nan'
    if math.isinf(x): return 'infinity'
    x=abs(x)
    if x == 0: return float.fromhex('0x0.0000000000001p-1022').hex()
    m,e=math.frexp(x)
    e=max(e-53,-1074)
    return math.ldexp(1.0,e).hex()
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('zero', solve(0), '0x0.0000000000001p-1022')
check('negative zero', solve(1<<63), '0x0.0000000000001p-1022')
check('subnormal', solve(N), '0x0.0000000000001p-1022')
check('power boundary', solve((1023+N)<<52), math.ldexp(1.0,N-52).hex())
check('negative power', solve((1<<63)|((1023+N)<<52)), math.ldexp(1.0,N-52).hex())
check('below power', solve(((1023+N)<<52)-1), math.ldexp(1.0,N-53).hex())
check('infinity', solve(0x7ff0000000000000), 'infinity')
check('nan', solve(0x7ff8000000000000|N), 'nan')
check('maximum', solve(0x7fefffffffffffff), '0x1.0000000000000p+971')
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
zero0x0.0000000000001p-10220x0.0000000000001p-1022Passed
negative zero0x0.0000000000001p-10220x0.0000000000001p-1022Passed
subnormal0x0.0000000000001p-10220x0.0000000000001p-1022Passed
power boundary0x1.0000000000000p-510x1.0000000000000p-51Passed
negative power0x1.0000000000000p-510x1.0000000000000p-51Passed
below power0x1.0000000000000p-520x1.0000000000000p-52Passed
infinityinfinityinfinityPassed
nannannanPassed
maximum0x1.0000000000000p+9710x1.0000000000000p+971Passed

SHA-256 / 2d845f1224db3a884bf6208ebd3d50326ec5c32e26c953c914127acaad9dc1f2

Verification & scope

Controlled binary64 or explicitly stipulated miniature format; no hardware exception flags or platform floating environment are modeled. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:39:31.454807+00:00.

Case digest / 7ee8e3e6af5a5e104bb8e492f3247fd553f30aca61d46c54243df3484a0fde2a