FAILURE MAP
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FA-15636 / Numerics / Open access

Binary polynomial division: quotient remainder result positions · case 01

The exact binary polynomial division result violates the stated contract at quotient remainder result positions.

Verified by executionVariant 1 · 8 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

The quotient remainder result positions step uses [a,q] instead of [q,a].

THE FAILURE

The quotient remainder result positions step uses [a,q] instead of [q,a].

Unsuccessful approach: The partial repair [q,a&1] still violates the quotient remainder result positions invariant.

Case contract

Input [a,b] integer bitmasks for F2 polynomials with b>0; return [quotient,remainder] of carryless division. Bounds: a,b<2^32.

Why this case matters

Exact discrete arithmetic with observable algorithmic state; no floating point approximation is used.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import itertools
from fractions import Fraction
N = 1
observations = []
def solve(x):
    a,b=x;q=0
    for _ in range(40):
     if a.bit_length()<b.bit_length():break
     shift=a.bit_length()-b.bit_length()
     if shift<0:return None
     q=q^(1<<shift)
     a=a^(b<<shift)
    return [a,q]
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[([1, 1], [1, 0]), ([2, 4], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([0, 2], [0, 0]), ([0, 3], [0, 0]), ([0, 4], [0, 0]), ([0, 5], [0, 0])], [([1, 2], [0, 1]), ([2, 7], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([0, 18], [0, 0]), ([0, 19], [0, 0]), ([0, 20], [0, 0]), ([0, 21], [0, 0])], [([1, 3], [0, 1]), ([2, 10], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([1, 4], [0, 1]), ([1, 5], [0, 1]), ([1, 6], [0, 1]), ([1, 7], [0, 1])], [([1, 4], [0, 1]), ([2, 13], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([1, 21], [0, 1]), ([1, 22], [0, 1]), ([1, 23], [0, 1]), ([1, 24], [0, 1])], [([1, 5], [0, 1]), ([2, 16], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([2, 7], [0, 2]), ([2, 8], [0, 2]), ([2, 9], [0, 2]), ([2, 10], [0, 2])]]
for i, (args, expected) in enumerate(fixtures[N-1]):
    check("explicit oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
explicit oracle 0[0, 1][1, 0]Failed
explicit oracle 1[2, 0][0, 2]Failed
explicit oracle 2[0, 0][0, 0]Passed
explicit oracle 3[3, 4][4, 3]Failed
explicit oracle 4[0, 0][0, 0]Passed
explicit oracle 5[0, 0][0, 0]Passed
explicit oracle 6[0, 0][0, 0]Passed
explicit oracle 7[0, 0][0, 0]Passed

SHA-256 / 5de021d5c13f4035d449bdde592e39dd3394192db17f26e7c37e16c7d70469f4

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
import math
import itertools
from fractions import Fraction
N = 1
observations = []
def solve(x):
    a,b=x;q=0
    for _ in range(40):
     if a.bit_length()<b.bit_length():break
     shift=a.bit_length()-b.bit_length()
     if shift<0:return None
     q=q^(1<<shift)
     a=a^(b<<shift)
    return [q,a&1]
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[([1, 1], [1, 0]), ([2, 4], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([0, 2], [0, 0]), ([0, 3], [0, 0]), ([0, 4], [0, 0]), ([0, 5], [0, 0])], [([1, 2], [0, 1]), ([2, 7], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([0, 18], [0, 0]), ([0, 19], [0, 0]), ([0, 20], [0, 0]), ([0, 21], [0, 0])], [([1, 3], [0, 1]), ([2, 10], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([1, 4], [0, 1]), ([1, 5], [0, 1]), ([1, 6], [0, 1]), ([1, 7], [0, 1])], [([1, 4], [0, 1]), ([2, 13], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([1, 21], [0, 1]), ([1, 22], [0, 1]), ([1, 23], [0, 1]), ([1, 24], [0, 1])], [([1, 5], [0, 1]), ([2, 16], [0, 2]), ([0, 1], [0, 0]), ([127, 31], [4, 3]), ([2, 7], [0, 2]), ([2, 8], [0, 2]), ([2, 9], [0, 2]), ([2, 10], [0, 2])]]
for i, (args, expected) in enumerate(fixtures[N-1]):
    check("explicit oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
explicit oracle 0[1, 0][1, 0]Passed
explicit oracle 1[0, 0][0, 2]Failed
explicit oracle 2[0, 0][0, 0]Passed
explicit oracle 3[4, 1][4, 3]Failed
explicit oracle 4[0, 0][0, 0]Passed
explicit oracle 5[0, 0][0, 0]Passed
explicit oracle 6[0, 0][0, 0]Passed
explicit oracle 7[0, 0][0, 0]Passed

SHA-256 / 6286184836fcf355210383b6eb9947749789e6f0e7b7a0fcfb4c04cf8e9b9675

HELD IN THE MEMBER ARCHIVE

The verified repair and its recorded checks are member-only.

This mechanism has 8 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.

Every case sharing this mechanism uses the same contract and the same repair, so this one record is held back for all of them.

Member access is invitation-based. Sign in with your invited account to inspect the repair.

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Verification & scope

A deterministic bounded teaching model. Inputs are restricted to the explicit contract; this is not a production algebra library. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:39:28.776606+00:00.

Case digest / 9b665794a0c7ad8f23e9afc375839093b38f0955fbefe70ae022b7f55d0a69e0