FA-14836 / Numerics / Open access
Polynomial squarefree characteristic p: unit gcd criterion · case 01
The exact polynomial squarefree characteristic p result violates the stated contract at unit gcd criterion.
ROOT CAUSE
The unit gcd criterion step uses bool(f) instead of len(f)==1.
VERIFIED REPAIR
Use len(f)==1 at the unit gcd criterion step.
Unsuccessful approach: The partial repair len(f)<=2 still violates the unit gcd criterion invariant.
Case contract
Input [coefficients,p] prime p; return whether nonconstant polynomial over Fp has gcd(f,fprime)=1; constants false. Bounds: degree at most three and prime p<=7.
Why this case matters
Exact discrete arithmetic with observable algorithmic state; no floating point approximation is used.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
import itertools
from fractions import Fraction
N = 1
observations = []
def solve(x):
a,p=x
f=[v%p for v in a]
while f and f[-1]==0:f.pop()
if len(f)<2:return False
g=[(i*f[i])%p for i in range(1,len(f))]
while g and g[-1]==0:g.pop()
for _ in range(20):
if not g:break
r=f[:]
for _ in range(20):
if len(r)<len(g):break
if g[-1]%p==0:return None
c=r[-1]*pow(g[-1],-1,p)%p
k=len(r)-len(g)
for j in range(len(g)):r[j+k]=(r[j+k]-c*g[j])%p
while r and r[-1]==0:r.pop()
f,g=g,r
return bool(f)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[([[0, 0, 1], 2], False), ([[0, 0, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 2], 2], False), ([[1, 1], 2], True), ([[1, 2], 2], False), ([[2, 1], 2], True)], [([[0, 2, 1], 2], False), ([[1, 2, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 2, 2], 2], False), ([[2, 0, 1], 2], False), ([[2, 0, 2], 2], False), ([[2, 1, 1], 2], True)], [([[1, 0, 1], 2], False), ([[0, 0, 1, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 1, 2, 1], 2], False), ([[0, 1, 2, 2], 2], True), ([[0, 2, 0, 1], 2], False), ([[0, 2, 0, 2], 2], False)], [([[1, 2, 1], 2], False), ([[0, 0, 2, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 1, 1, 2], 2], True), ([[1, 1, 2, 1], 2], True), ([[1, 1, 2, 2], 2], True), ([[1, 2, 0, 1], 2], True)], [([[2, 0, 1], 2], False), ([[0, 2, 1, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[2, 1, 1, 1], 2], True), ([[2, 1, 1, 2], 2], True), ([[2, 1, 2, 1], 2], False), ([[2, 1, 2, 2], 2], True)]]
for i, (args, expected) in enumerate(fixtures[N-1]):
check("explicit oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| explicit oracle 0 | True | False | Failed |
| explicit oracle 1 | True | False | Failed |
| explicit oracle 2 | True | True | Passed |
| explicit oracle 3 | True | True | Passed |
| explicit oracle 4 | False | False | Passed |
| explicit oracle 5 | True | True | Passed |
| explicit oracle 6 | False | False | Passed |
| explicit oracle 7 | True | True | Passed |
SHA-256 / 74f3dfca93285d258c22c7921a89c9d2d062b6724cad6e38f10492950d4662b4
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
import itertools
from fractions import Fraction
N = 1
observations = []
def solve(x):
a,p=x
f=[v%p for v in a]
while f and f[-1]==0:f.pop()
if len(f)<2:return False
g=[(i*f[i])%p for i in range(1,len(f))]
while g and g[-1]==0:g.pop()
for _ in range(20):
if not g:break
r=f[:]
for _ in range(20):
if len(r)<len(g):break
if g[-1]%p==0:return None
c=r[-1]*pow(g[-1],-1,p)%p
k=len(r)-len(g)
for j in range(len(g)):r[j+k]=(r[j+k]-c*g[j])%p
while r and r[-1]==0:r.pop()
f,g=g,r
return len(f)<=2
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[([[0, 0, 1], 2], False), ([[0, 0, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 2], 2], False), ([[1, 1], 2], True), ([[1, 2], 2], False), ([[2, 1], 2], True)], [([[0, 2, 1], 2], False), ([[1, 2, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 2, 2], 2], False), ([[2, 0, 1], 2], False), ([[2, 0, 2], 2], False), ([[2, 1, 1], 2], True)], [([[1, 0, 1], 2], False), ([[0, 0, 1, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 1, 2, 1], 2], False), ([[0, 1, 2, 2], 2], True), ([[0, 2, 0, 1], 2], False), ([[0, 2, 0, 2], 2], False)], [([[1, 2, 1], 2], False), ([[0, 0, 2, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 1, 1, 2], 2], True), ([[1, 1, 2, 1], 2], True), ([[1, 1, 2, 2], 2], True), ([[1, 2, 0, 1], 2], True)], [([[2, 0, 1], 2], False), ([[0, 2, 1, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[2, 1, 1, 1], 2], True), ([[2, 1, 1, 2], 2], True), ([[2, 1, 2, 1], 2], False), ([[2, 1, 2, 2], 2], True)]]
for i, (args, expected) in enumerate(fixtures[N-1]):
check("explicit oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| explicit oracle 0 | False | False | Passed |
| explicit oracle 1 | True | False | Failed |
| explicit oracle 2 | True | True | Passed |
| explicit oracle 3 | True | True | Passed |
| explicit oracle 4 | False | False | Passed |
| explicit oracle 5 | True | True | Passed |
| explicit oracle 6 | False | False | Passed |
| explicit oracle 7 | True | True | Passed |
SHA-256 / 72dcf898ab76465c902bd8049b0803d07791815347258cc92d4e5c86b1fc29d3
3 / The verified repair
Exit 0"""Failure Map reference implementation. Python standard library only."""
import json
import math
import itertools
from fractions import Fraction
N = 1
observations = []
def solve(x):
a,p=x
f=[v%p for v in a]
while f and f[-1]==0:f.pop()
if len(f)<2:return False
g=[(i*f[i])%p for i in range(1,len(f))]
while g and g[-1]==0:g.pop()
for _ in range(20):
if not g:break
r=f[:]
for _ in range(20):
if len(r)<len(g):break
if g[-1]%p==0:return None
c=r[-1]*pow(g[-1],-1,p)%p
k=len(r)-len(g)
for j in range(len(g)):r[j+k]=(r[j+k]-c*g[j])%p
while r and r[-1]==0:r.pop()
f,g=g,r
return len(f)==1
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
fixtures = [[([[0, 0, 1], 2], False), ([[0, 0, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 2], 2], False), ([[1, 1], 2], True), ([[1, 2], 2], False), ([[2, 1], 2], True)], [([[0, 2, 1], 2], False), ([[1, 2, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 2, 2], 2], False), ([[2, 0, 1], 2], False), ([[2, 0, 2], 2], False), ([[2, 1, 1], 2], True)], [([[1, 0, 1], 2], False), ([[0, 0, 1, 1], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[0, 1, 2, 1], 2], False), ([[0, 1, 2, 2], 2], True), ([[0, 2, 0, 1], 2], False), ([[0, 2, 0, 2], 2], False)], [([[1, 2, 1], 2], False), ([[0, 0, 2, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[1, 1, 1, 2], 2], True), ([[1, 1, 2, 1], 2], True), ([[1, 1, 2, 2], 2], True), ([[1, 2, 0, 1], 2], True)], [([[2, 0, 1], 2], False), ([[0, 2, 1, 2], 3], False), ([[0, 1], 2], True), ([[2, 2, 2, 2], 7], True), ([[2, 1, 1, 1], 2], True), ([[2, 1, 1, 2], 2], True), ([[2, 1, 2, 1], 2], False), ([[2, 1, 2, 2], 2], True)]]
for i, (args, expected) in enumerate(fixtures[N-1]):
check("explicit oracle %d" % i, solve(args), expected)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| explicit oracle 0 | False | False | Passed |
| explicit oracle 1 | False | False | Passed |
| explicit oracle 2 | True | True | Passed |
| explicit oracle 3 | True | True | Passed |
| explicit oracle 4 | False | False | Passed |
| explicit oracle 5 | True | True | Passed |
| explicit oracle 6 | False | False | Passed |
| explicit oracle 7 | True | True | Passed |
SHA-256 / d2f0cee60803ccf181d82bc61dc8a9059767d13c3816a0d5050bc5b9de147cfc
Verification & scope
A deterministic bounded teaching model. Inputs are restricted to the explicit contract; this is not a production algebra library. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-29T14:39:20.696077+00:00.
Case digest / 5fef82c350a92dcf46d702154d4ec7daab3b053c1f0bffb76b47bb8a3ac833c9