FAILURE MAP
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FA-13771 / Numerical aggregation / Open access

Adjusted partition pair agreement: Chance agreement uses a sum of marginal pair totals. · case 01

The reduction disagrees with its explicit aggregation oracle.

Verified by executionVariant 1 · 9 checks per implementationDownload source bundle ↓JSON ↗

ROOT CAUSE

Chance agreement uses a sum of marginal pair totals.

VERIFIED REPAIR

Preserve the adjusted partition pair agreement contract at the identified reduction decision.

Unsuccessful approach: Normalizing by pair count twice turns expected pair count into a probability.

Case contract

Two equal-length integer cluster label arrays describe the same observations. Return exact adjusted Rand index from pair-count contingency reduction. Label names have no numerical meaning. Matching degenerate partitions with zero normalization return "1"; length mismatch returns None.

Why this case matters

Exact bounded examples isolate a reduction defect without floating-point or external-service effects.

1 / The failure

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
from fractions import Fraction
from collections import Counter, defaultdict
import math
import itertools
N = 1
observations = []
def solve(a, b):
    if len(a)!=len(b): return None
    n=len(a)
    if n<2: return "1"
    pairs=n*(n-1)//2
    joint=Counter(zip(a,b))
    ra,rb=Counter(a),Counter(b)
    choose=lambda k:k*(k-1)//2
    same=sum(choose(v) for v in joint.values())
    x=sum(choose(v) for v in ra.values())
    y=sum(choose(v) for v in rb.values())
    expected=Fraction(x+y,pairs)
    ceiling=Fraction(x+y,2)
    return "1" if ceiling==expected else str((same-expected)/(ceiling-expected))
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('regression 1', solve(*([0, 0, 1, 1], [4, 4, 5, 5])), '1')
check('regression 2', solve(*([0, 0, 1, 1], [0, 1, 0, 1])), '-1/2')
check('regression 3', solve(*([], [])), '1')
check('regression 4', solve(*([0], [9])), '1')
check('regression 5', solve(*([0, 0, 0, 1, 2], [1, 1, 2, 2, 2])), '-2/23')
check('regression 6', solve(*([0, 1, 2], [8, 9, 10])), '1')
check('regression 7', solve(*([0, 0], [1])), None)
check('regression 8', solve(*([0, 0, 1, 2, 2, 2], [4, 5, 4, 5, 5, 5])), '34/109')
check("variable label names",solve([N,N,N+1,N+1],[7,7,8,8]),"1")
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
regression 111Passed
regression 2-1/2-1/2Passed
regression 311Passed
regression 411Passed
regression 53/28-2/23Failed
regression 611Passed
regression 7NoneNonePassed
regression 868/14334/109Failed
variable label names11Passed

SHA-256 / d70d0fe2c31e80172ab13e4b9e95ce8bab16fde71b80407c60b199e3081f0567

2 / The unsuccessful fix

Exit 1
"""Failure Map reference implementation. Python standard library only."""
import json
from fractions import Fraction
from collections import Counter, defaultdict
import math
import itertools
N = 1
observations = []
def solve(a, b):
    if len(a)!=len(b): return None
    n=len(a)
    if n<2: return "1"
    pairs=n*(n-1)//2
    joint=Counter(zip(a,b))
    ra,rb=Counter(a),Counter(b)
    choose=lambda k:k*(k-1)//2
    same=sum(choose(v) for v in joint.values())
    x=sum(choose(v) for v in ra.values())
    y=sum(choose(v) for v in rb.values())
    expected=Fraction(x*y,pairs*pairs)
    ceiling=Fraction(x+y,2)
    return "1" if ceiling==expected else str((same-expected)/(ceiling-expected))
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('regression 1', solve(*([0, 0, 1, 1], [4, 4, 5, 5])), '1')
check('regression 2', solve(*([0, 0, 1, 1], [0, 1, 0, 1])), '-1/2')
check('regression 3', solve(*([], [])), '1')
check('regression 4', solve(*([0], [9])), '1')
check('regression 5', solve(*([0, 0, 0, 1, 2], [1, 1, 2, 2, 2])), '-2/23')
check('regression 6', solve(*([0, 1, 2], [8, 9, 10])), '1')
check('regression 7', solve(*([0, 0], [1])), None)
check('regression 8', solve(*([0, 0, 1, 2, 2, 2], [4, 5, 4, 5, 5, 5])), '34/109')
check("variable label names",solve([N,N,N+1,N+1],[7,7,8,8]),"1")
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
regression 111Passed
regression 2-1/17-1/2Failed
regression 311Passed
regression 411Passed
regression 544/169-2/23Failed
regression 611Passed
regression 7NoneNonePassed
regression 81294/241934/109Failed
variable label names11Passed

SHA-256 / 123877e1265f94054ae45f5c270058e1908292b5a4cb8a0ceae79f7d29aa3d9b

3 / The verified repair

Exit 0
"""Failure Map reference implementation. Python standard library only."""
import json
from fractions import Fraction
from collections import Counter, defaultdict
import math
import itertools
N = 1
observations = []
def solve(a, b):
    if len(a)!=len(b): return None
    n=len(a)
    if n<2: return "1"
    pairs=n*(n-1)//2
    joint=Counter(zip(a,b))
    ra,rb=Counter(a),Counter(b)
    choose=lambda k:k*(k-1)//2
    same=sum(choose(v) for v in joint.values())
    x=sum(choose(v) for v in ra.values())
    y=sum(choose(v) for v in rb.values())
    expected=Fraction(x*y,pairs)
    ceiling=Fraction(x+y,2)
    return "1" if ceiling==expected else str((same-expected)/(ceiling-expected))
def check(label, actual, expected):
    observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('regression 1', solve(*([0, 0, 1, 1], [4, 4, 5, 5])), '1')
check('regression 2', solve(*([0, 0, 1, 1], [0, 1, 0, 1])), '-1/2')
check('regression 3', solve(*([], [])), '1')
check('regression 4', solve(*([0], [9])), '1')
check('regression 5', solve(*([0, 0, 0, 1, 2], [1, 1, 2, 2, 2])), '-2/23')
check('regression 6', solve(*([0, 1, 2], [8, 9, 10])), '1')
check('regression 7', solve(*([0, 0], [1])), None)
check('regression 8', solve(*([0, 0, 1, 2, 2, 2], [4, 5, 4, 5, 5, 5])), '34/109')
check("variable label names",solve([N,N,N+1,N+1],[7,7,8,8]),"1")
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
Boundary fixtureActualExpectedOutcome
regression 111Passed
regression 2-1/2-1/2Passed
regression 311Passed
regression 411Passed
regression 5-2/23-2/23Passed
regression 611Passed
regression 7NoneNonePassed
regression 834/10934/109Passed
variable label names11Passed

SHA-256 / f1d717731848ae1508be0aed6706e7ae4b085082a44842998adbcafe1bc5ec7c

Verification & scope

Small offline integer/rational inputs only; no performance, statistical inference, or production-library conformance claim. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.

Observations recorded using Python 3.12.14 at 2026-09-29T14:39:10.358449+00:00.

Case digest / b39361de66f89570925a28840a8dc361e61e8102b51fbc187f902dbdaf2a48b1