FA-11706 / Graph algorithm invariants / Open access
Duplicate dependency declarations strand a valid topological vertex · case 01
Duplicate dependency declarations strand a valid topological vertex.
ROOT CAUSE
Indegree counts duplicate declarations while outgoing adjacency deduplicates them, so decrements cannot balance increments.
THE FAILURE
Indegree counts duplicate declarations while outgoing adjacency deduplicates them, so decrements cannot balance increments.
Unsuccessful approach: Ignoring a stranded suffix by returning the processed prefix conceals cycles and missing vertices.
Case contract
Treat repeated directed edges as one dependency. Return the lexicographically smallest topological order, or None if any cycle exists. Include isolated vertices.
Why this case matters
A deterministic in-memory graph model isolates this invariant; no large-graph performance or production graph engine behavior is claimed.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
from itertools import combinations
N = 1
observations = []
def solve(vertices, edges):
adj = {v:set() for v in vertices}
indegree = {v:0 for v in vertices}
for u,v in edges:
indegree[v] += 1
adj[u].add(v)
ready = sorted(v for v in vertices if indegree[v] == 0)
answer = []
while ready:
u = ready.pop(0); answer.append(u)
for v in sorted(adj[u]):
indegree[v] -= 1
if indegree[v] == 0: ready.append(v)
ready.sort()
return answer if len(answer) == len(vertices) else None
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
a,b,c = N,N+1,N+2
check('duplicate dependency', solve([a,b], [(a,b),(a,b)]), [a,b])
check('cycle with independent prefix', solve([a,b,c], [(b,c),(c,b)]), None)
check('self cycle', solve([a], [(a,a)]), None)
check('empty', solve([], []), [])
check('isolated lexicographic order', solve([c,a,b], []), [a,b,c])
check('reverse dependency', solve([a,b,c], [(c,a)]), [b,c,a])
check('diamond duplicate', solve([a,b,c], [(a,c),(b,c),(b,c)]), [a,b,c])
check('variable-length dependency chain', solve(list(range(N+1)), [(i,i+1) for i in range(N)]), list(range(N+1)))
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| duplicate dependency | None | [1, 2] | Failed |
| cycle with independent prefix | None | None | Passed |
| self cycle | None | None | Passed |
| empty | [] | [] | Passed |
| isolated lexicographic order | [1, 2, 3] | [1, 2, 3] | Passed |
| reverse dependency | [2, 3, 1] | [2, 3, 1] | Passed |
| diamond duplicate | None | [1, 2, 3] | Failed |
| variable-length dependency chain | [0, 1] | [0, 1] | Passed |
SHA-256 / e750dafde75a1135387989754d30075deb966505e52feeb28950d1721bcbb3f5
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
from itertools import combinations
N = 1
observations = []
def solve(vertices, edges):
adj = {v:set() for v in vertices}
indegree = {v:0 for v in vertices}
for u,v in edges:
if v not in adj[u]: indegree[v] += 1
adj[u].add(v)
ready = sorted(v for v in vertices if indegree[v] == 0)
answer = []
while ready:
u = ready.pop(0); answer.append(u)
for v in sorted(adj[u]):
indegree[v] -= 1
if indegree[v] == 0: ready.append(v)
ready.sort()
return answer
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
a,b,c = N,N+1,N+2
check('duplicate dependency', solve([a,b], [(a,b),(a,b)]), [a,b])
check('cycle with independent prefix', solve([a,b,c], [(b,c),(c,b)]), None)
check('self cycle', solve([a], [(a,a)]), None)
check('empty', solve([], []), [])
check('isolated lexicographic order', solve([c,a,b], []), [a,b,c])
check('reverse dependency', solve([a,b,c], [(c,a)]), [b,c,a])
check('diamond duplicate', solve([a,b,c], [(a,c),(b,c),(b,c)]), [a,b,c])
check('variable-length dependency chain', solve(list(range(N+1)), [(i,i+1) for i in range(N)]), list(range(N+1)))
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| duplicate dependency | [1, 2] | [1, 2] | Passed |
| cycle with independent prefix | [1] | None | Failed |
| self cycle | [] | None | Failed |
| empty | [] | [] | Passed |
| isolated lexicographic order | [1, 2, 3] | [1, 2, 3] | Passed |
| reverse dependency | [2, 3, 1] | [2, 3, 1] | Passed |
| diamond duplicate | [1, 2, 3] | [1, 2, 3] | Passed |
| variable-length dependency chain | [0, 1] | [0, 1] | Passed |
SHA-256 / 81b0cebea6659f9eac2b19938be35b6f26c9e0c311be89fcd26fe66f3b5d495b
HELD IN THE MEMBER ARCHIVE
The verified repair and its recorded checks are member-only.
This mechanism has 8 recorded checks per implementation. The open-access tier publishes the failure and the unsuccessful fix; the repaired source that passes every check, and the observations that prove it, are available to members.
Every case sharing this mechanism uses the same contract and the same repair, so this one record is held back for all of them.
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Sign in to the archive ↗Verification & scope
Small explicit graphs only; exhaustive reference algorithms emphasize semantics rather than asymptotic performance. This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-29T14:38:50.321386+00:00.
Case digest / 7e5c1a59b63d177df625c7846993fe6e4cd26297f1a040cf922a482e7183fbdb