FA-11071 / Media playlist state / Open access
Explicit skip bypasses repeat one · case 01
The natural-completion repeat-one rule traps an explicit skip on the same entry.
ROOT CAUSE
The natural-completion repeat-one rule traps an explicit skip on the same entry.
VERIFIED REPAIR
Preserve the media contract: An explicit user skip advances despite repeat-one; only repeat-all wraps at playlist end. Current is valid in nonempty playlist.
Unsuccessful approach: Wrapping every skip makes a nonrepeating playlist restart at the end.
Case contract
An explicit user skip advances despite repeat-one; only repeat-all wraps at playlist end. Current is valid in nonempty playlist.
Why this case matters
A deterministic local media controller stage; metadata and downloaded data are supplied explicitly. No external player, service or codec is required.
1 / The failure
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
N = 1
observations = []
def solve(current, length, repeat):
return current if repeat=="one" else (current+1 if current+1<length else None)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1',solve(*(0, 3, 'one')),1)
check('fixture 2',solve(*(2, 3, 'one')),None)
check('fixture 3',solve(*(2, 3, 'all')),0)
check('fixture 4',solve(*(2, 3, 'off')),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| fixture 1 | 0 | 1 | Failed |
| fixture 2 | 2 | None | Failed |
| fixture 3 | None | 0 | Failed |
| fixture 4 | None | None | Passed |
SHA-256 / 4fd15ea7bf9080bb27865faafe5313ccda84067329a716db67d1d87b08c76b4c
2 / The unsuccessful fix
Exit 1"""Failure Map reference implementation. Python standard library only."""
import json
import math
N = 1
observations = []
def solve(current, length, repeat):
return (current+1)%length
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1',solve(*(0, 3, 'one')),1)
check('fixture 2',solve(*(2, 3, 'one')),None)
check('fixture 3',solve(*(2, 3, 'all')),0)
check('fixture 4',solve(*(2, 3, 'off')),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| fixture 1 | 1 | 1 | Passed |
| fixture 2 | 0 | None | Failed |
| fixture 3 | 0 | 0 | Passed |
| fixture 4 | 0 | None | Failed |
SHA-256 / fe1fde18854562495ac5d3b3284d0bddc078fbb8b2e025b8c12b1f80897da458
3 / The verified repair
Exit 0"""Failure Map reference implementation. Python standard library only."""
import json
import math
N = 1
observations = []
def solve(current, length, repeat):
return current+1 if current+1<length else (0 if repeat=="all" else None)
def check(label, actual, expected):
observations.append({"check": label, "actual": actual, "expected": expected, "passed": actual == expected})
check('fixture 1',solve(*(0, 3, 'one')),1)
check('fixture 2',solve(*(2, 3, 'one')),None)
check('fixture 3',solve(*(2, 3, 'all')),0)
check('fixture 4',solve(*(2, 3, 'off')),None)
print(json.dumps({"observations": observations, "passed": all(x["passed"] for x in observations)}, ensure_ascii=False))
raise SystemExit(0 if all(x["passed"] for x in observations) else 1)
| Boundary fixture | Actual | Expected | Outcome |
|---|---|---|---|
| fixture 1 | 1 | 1 | Passed |
| fixture 2 | None | None | Passed |
| fixture 3 | 0 | 0 | Passed |
| fixture 4 | None | None | Passed |
SHA-256 / 27bc1fb9880db3d24f8a76cf518481570f0a2ab35925166ed8ede512b3683da8
Verification & scope
This reproducer isolates one failure mechanism. Results cover the supplied fixtures. Variants within a family share a test contract and should remain grouped when constructing evaluation splits. Related mechanisms with a shared evaluation_group must also remain together; these controlled models are not independent production incidents.
Observations recorded using Python 3.12.14 at 2026-09-29T14:38:44.748809+00:00.
Case digest / 72900fdfa1eaa0a42abc11b9948be96ae2bdf9b156ea397bf7f87cbd3a0892e2